your answer key question 59 part c efficiency

bill g ( billg5@yahoo.com )
Fri, 30 Apr 1999 07:34:31 -0700 (PDT)

can you help me with q59 woll efficiencies part c


if we assume the variance is .3050 the popular
answer then are we using
wolls first formula, wolls second formula or
what????

var(x)=.3050 e(x)=.2547, the frequency per jim shoenfelts excellent
answer sheet


wolls first formula gives var(m)=
var(x)-e(x)=.305-.2547=.0503

e(m)=e(x)=.2547;

so cv(m)= sqrt(var(m))/e(m) =
sqrt(.0503)/.2547=.88055208

so efficiency = cv^2 insurance plan/cv^2 pop =
(.88055208/1.1)^2=

.64080 my answer to part c.

can you tell me what is happening here is this wolls
first formula or some other formula, is this correct???

thanks for your help
billg

billg5@yahoo.com
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