E(X)= ((126*1)+(52*2))/903 = .255
Var (X) = E(X^2)-(E(X)^2)
E(X^2)= ((126*1)+(52*4))/903 = .370
Var(X)=.370 - (.255)^2 = .305
Var(M)= .305 - .255 = .05
However, I think the coefficient of variation^2 should be
(Var(M))/(E(M)^2) = (.305)/(.255)^2 = 2.166
Efficiency = 2.166/(1.1)^2 = 1.79
Since I just figured out the Woll formulas a couple of days ago and am not
positive, I hope that this is correct.
Faith