Re: Chapter 17, Quiz 9b (page 469)

Michael McKenney ( mmckenne@ins.state.pa.us )
Tue, 25 Aug 1998 11:42:49 -0400

The solution is as follows:

R(e) = .15 = .10 + 1.5(R(m) - .10)
.05 = 1.5 R(m) - .15
.20 = 1.5 R(m)
.133 = R(m)

the .10 is R(d) found in 9a.

At 10:21 AM 8/25/98 -0700, Janette Mosley wrote:
>Does anyone have the solution worked out? The answer is in the back of
>the book, but no one here can figure it out. Thx!
>
>