This substitution leaves you with the integrand... [(u-10)du]/u^2 or
[du/u - 10du/u^2]
This is easily integrable, but be sure to switch your limits of integration from
0 and 5, to 10 and 15.
Without simplifying, I got as an answer... ln(15) - ln(10) + 10/15 -
10/10
This can simplify to... ln(3/2) - 1/3 = .072
Chris