> (4) For number 10 I get none of the above! The 50 type Y's
> below the limit contribute f(y). The 75 type Y's above the
> limit each contribute 1-F(k). The 75 type Z's above the
> deductible each contribute f(z)/[1-F(k)]. Thus we have the
> numerator from an> swers B and D, but the denominator from
> answer E. COMMENTS?
No, I think multiplying exactly what you wrote gives (A).
You would have had the correct solution yet possibly circled
the wrong answer on the actual exam :-)
Incidentally, this is problem 27 from the Spring 1998 exam.
David Scollnik
-- David P.M. Scollnik , Ph.D. , A.S.A. (403) 220 7677 Dept of Math and Stats , Univ of Calgary or (403) 220 5202 scollnik@acs.ucalgary.ca ++ http://balducci.math.ucalgary.ca