RE: Re[2]: Study Manual 4b, Fall 1998

Scherr, Vickie ( (no email) )
Wed, 9 Sep 1998 11:04:48 -0500

Suppose k=1.76 and x=2. Then you have:

(2.76)
( 2 ).

That leads to 2.76! / (2! 0.76!) = 2.76 * 1.76 * 0.76! / 2 * 0.76!

The 0.76!'s cancel and you're left with 2.76 * 1.76 / 2.

Vickie

-----Original Message-----
From: christian.coleianne@zurich.com
[mailto:christian.coleianne@zurich.com]
Sent: Wednesday, September 09, 1998 10:57 AM
To: (Cathy McEvoy)
Cc: studygroup4b@lists.casact.org
Subject: Re: Re[2]: Study Manual 4b, Fall 1998

I don't understand how you got a non-integer for the k value. That may
be
where the problem lies.

After that, I would compare the probability of x to the empirical
frequency
in the
numerator.

To: studygroup4b <studygroup4b@lists.casact.org>
cc: (bcc: Christian Coleianne/MCIG/USA/Zurich)
Subject: Re[2]: Study Manual 4b, Fall 1998

I wonder if you could help. I'm having a mental block on decimal
factorials.

Specifically, I was doing a Pearson's Chi-square problem with a
fitted
negative binomial. The K parameter was 1.76. So, how do I go
about
solving for different values of x:

( x+k-1)
( ) p^k q^x ?
( x )

Thanks!