Herzog exercise

Annette Thomas ( (no email) )
Tue, 30 Jun 1998 16:04:38 -0500

Has anyone worked exercise 2-5, Herzog, page 21. My solution is
..036769/.037082=.9916 which is equivalent to Herzog's solution 5.9/5.95.

I need an explanation of why Herzog states a ratio of probabilities as
the ratio of two numbers greater than 1.00.

If the solution is truly .059/.0595 or something similar please tell how
to get there.

Thanks!