> "probability of decrement due to 2nd cause" means you need to find
(2)
oo q 65
The "oo" is an infinity. It's the probably that a life age 65 decrements due
to cause (2) ever.
You find this using the fact that the sum of q due to (1) and q due to (2)
is equal to q (total).
Also,
(T)
oo q 65 = 1 (probably of dying ever)
Then you calculate
(1)
oo q 65 as equal to the integral of force of mortality (1) times t p x.
I think those are the main points needed for the solution. Let me know if
its not clear.
> ----------
> From: Fernando Alvarado Angulo[SMTP:falvarad@cu.gdl.uag.mx]
> Sent: Friday, October 29, 1999 3:38 PM
> To: studygroup4A@lists.casact.org
> Subject: May 1999 #23
>
>
> Hi,
>
> I missed the answer to this one, if posted:
>
> (23) For a multiple decrement model with two causes of decrement, you are
> given the total force of decrement, mu^T(x+t) = 1/[100-(x+t)] and the
> force of decrement due to the first cause, mu^1(x+t) = 1/100.
> For (65), determine the probability of decrement due to the second cause.
>
> If anyone has it, would you mind posting it back? I have a doubt on what
> "probability of decrement due to 2nd cause" means. Do the problem asks
> simply for
> (2)
> q 65
>
> The probability that (65) will *decrement* during the following year due
> to cause 2?
>
> Thanx!
>