RE: CAS Manual p.441 Problem D#23

Medina, Hernan ( (no email) )
Fri, 29 Oct 1999 09:41:08 -0400

Completing the life table allows you to read off the
probability of survival. It does not matter what
starting values you use. I selected them so that
I would get integers when I applied the probability
of death.

k l(x+k) l(y+k)
------------------
0 160 100
1 120 50
2 30 25
3 0 0

a due(xy bar) = a due(x) + a due(y) - a due(xy)

a due(x) = 1 + v (120/160) + v squared (30/160)
a due(y) = 1 + v (50/100) + v squared (25/100)
a due(xy) = 1 + v (120/160)(50/100) +
v squared (30/160)(25/100)

Since the lives are independent, tPxy = tPx tPy

> ----------
> From: BrianOhlman[SMTP:Brian.Ohlman@thehartford.com]
> Sent: Friday, October 29, 1999 9:03 AM
> To: - *studygroup4a@lists.casact.org
> Subject: CAS Manual p.441 Problem D#23
>
> Would anyone be kind enough to explain this one:
>
> The curtate future lifetimes of a beneficiary aged x and her spouse
> aged y are subject to the following independent probabilities of
> death.
>
> k q(x+k) q(y+k)
>
> 0 .25 .50
> 1 .75 .50
> 2 1.00 1.00
>
> You may assume i=10%. Determine a(xy). The actuarial present value
> of an annuity payable at the beginning of each year as long as either
> beneficiary is alive.(note: a bar should be place over xy and dots
> over a).
>
>
>
>
> -Brian
>