> ----------
> From:
> Thomas_E._Meyer@sedgus.com[SMTP:Thomas_E._Meyer@sedgus.com]
> Sent: Friday, October 23, 1998 10:29AM
> To: studygroup4a@lists.casact.org
> Subject: Fall 97 exam question
>
> I know everyone busy cramming but if anyone has a second it would
> be
> much appreciated. Cannot figure out #15 from Fall 1997 exam. It
>
> reads:
>
> Your are given that: a(due)(30) = 20, 3V30 = 0.1 and 1V32 = 0.05
>
> Determine 1 - a(due)(33)(angle 1) / a(immediate)(32)
>
> (where a(due)(30) is PV of a life annunity due for 30 year old,
> 3V30
> is the reserve of a fully discrete whole life insurance issued at
> age
> 30 at t=3, a(due)(33)(angle 1) is 1-year tempary life annunity
> due for
> age 33.)
>
> a) less than .9400
> b) at least .9400, but less than 0.9425
> c) at least .9425, but less than .9450
> d) at least .9450, but less than .9475
> e) .9475 or more
>
>
> I can solve for a(immediate)(32) but for the life of me figure
> out
> what to do with the a(due)(33)(angle 1). even just a quick hint
> could
> help and i know most of us don't have time to do much else.
>
> Thanks
>
>